[nilesh]

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Hi buddy here I am looking for Data Interpretation sample question paper for IIFT MBA Entrance Exam Preparation, so would you plz provide me same here ??

[prince karak]

As you want here I am giving below Data Interpretation sample question paper for IIFT MBA Entrance Exam Preparation:

Directions for questions 1 to 3 : A team of 5 players Arpit, Bimal, Chatur, Dinu and Elan participated in a ‘Freaket’ tournament and played four matches (1 to 4). The following table gives partial information about their individual scores and the total runs scored by the team in each match.

Each column has two values missing. These are the runs scored by the two lowest scorers in that match.None of the two missing values is more than 10% of the total runs scored in that match.
Match-1 Match-2 Match-3 Match-4
Runs scored by player Arpit 100 53
Bimal 88 65 52
Chatur 110
Dinu 72 75 20 56
Elan 60 78
Total 270 300 240 200

1) What is the maximum possible percentage contribution of Arpit in the total runs scored in the four matches?

A. 19.7% B. 19.9%

C. 20.1% D. 20.2%

Answer: Option A

Explanation:

Maximum possible runs scored by Arpit in Match-1 = 27

Maximum possible runs scored by Arpit in Match-3 = 19

Maximum possible percentage contribution:

(27+100+19+53)/(270+300+240+200)x100% = 199/1010x100%
= 19.7%

2) If the absolute difference between the total runs scored by Arpit and Chatur in the four matches is minimum possible then what is the absolute difference between total runs scored by Bimal and Elan in the four matches?

A. 32 B. 37

C. 27 D. Cannot be determined

Answer: Option B

Explanation:

Maximum possible total runs scored by Chatur in the four matches = 27 + 30 + 110 + 20 = 187.

In such a case minimum possible total runs scored by Arpit in the four matches = 23 + 100 + 13 + 53 = 189.

Difference = 189 – 187 = 2 (minimum possible) Subsequently total runs scored by Bimal in the four matches = 88 + 65 + 19 + 52 = 224.

Also, total runs scored by Elan in the four matches = 60 + 30 + 78 + 19 = 187

Absolute difference = 224 – 187 = 37

3) The players are ranked 1 to 5 on the basis of the total runs scored by them in the four matches, with the highest scorer getting Rank 1. If it is known that no two players scored the same number of total runs, how many players are there whose rank can be exactly determined?

A. 0 B. 1

C. 3 D. 5

Answer: Option C

Explanation:

Individual ranges for total score:

Arpit-> 189-199

Bimal-> 218-224

Chatur-> 182-187

Dinu-> 223

Elan-> 187-188

Least total will be of Chatur (Rank 5)

2nd least will be Elan (Rank 4)

Rank 3 must be of Arpit.

It is not possible to determine the exact ranks of Bimal and Dinu.

II.

DIRECTIONS FOR QUESTIONS 1 to 5 :

RAILWAY TIMETABLE : NEW DELHI – BHUBANESWAR RAJDHANI EXPRESS

Station Name


Arrival Time


Departure Time


Distance(In KM)

New Delhi


--


17:05


0

Kanpur Central


21:48


21:53


440

Mughal Sarai JN


01:55


02:05


786

Gaya JN


04:18


04:21


989

Koderma


05:22


05:24


1066

Bokaro Steel City


07:35


07:40


1191

Tatanagar JN


10:35


10:40


1342

Kharagpur JN


12:25


12:40


1476

Balasore


14:02


14:04


1595

Bhadrak


15:12


15:14


1657

Cuttack


16:33


16:35


1772

Bhubaneswar


17:30


--


1800

Answer :

Station Name


Distance(In Km)


Time Taken(In hours)


Speed(In kmph)

New Delhi - Kanpur Central


440


4.72


93.22

Kanpur Central - Mughal Sarai JN


346


4.03


85.86

Mughal Sarai JN - Gaya JN


203


2.22


91.44

Gaya JN - Koderma


77


1.98


38.89

Koderma - Bokaro Steel City


125


2.18


57.34

Bokaro Steel City - Tatanagar JN


151


2.92


51.71

Tatanagar JN - Kharagpur JN


134


1.75


76.57

Kharagpur JN- Balasore


119


1.37


86.86

Balasore - Bhadrak


62


1.13


54.87

Bhadrak - Cuttack


115


1.32


87.12

Cuttack - Bhubaneswar


28


0.92


30.43

1.The longest run for the train between the two successive halts is

(a) Mughal Sarai JN - Gaya JN (b) New Delhi - Kanpur Central

(c) Kanpur Central - Mughal Sarai JN (d) Balasore - Balasore

Answer : Option b

Explanation :

With the run is of 440 km, the longest run is between New Delhi - Kanpur Central.

2. The average speed that the train maintained between two successive stations was the highest between

(a) Kanpur Central - Mughal Sarai JN (b) Mughal Sarai JN - Gaya JN

(c) New Delhi - Kanpur Central (d) Bokaro Steel City - Tatanagar JN

Answer : Option c

Explanation :

The average speed of 93.22 kmph is the highest between New Delhi - Kanpur Central.

3. The average speed that the train maintained between New Delhi and Bhubaneswar was nearly equal to

(a) 72 kmph (b) 74 kmph (c) 75 kmph (d) 82 kmph

Answer :

Explanation :

The average speed that the train maintained between New Delhi and Bhubaneswar = 1800 km/25 hrs and 25 min = 70.82 kmph.

4. If we consider a journey that begins in New Delhi and ends in Bhubaneswar, the train has the longest halt at

(a) Kanpur Central (b) Mughal Sarai JN (c) Tatanagar JN (d) Kharagpur JN

Answer : Option d