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pgcet eee paper |
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Re: pgcet eee paper
The Andhra Pradesh Post Graduation Engineering Common Entrance Test exam is conducted by the AP Board of Higher Education on behalf of Govt. of Andhra Pradesh. This Exam every year Conducting Osmania University is going to the examination. PGCET exam expected dates: Starting date to apply March 2017 Closing date to apply 3rd week of March 2017 Exam date May/ June 2017 Exam Pattern: Exam Type Subject Exam Paper Medium Total Questions Overall Marks Exam Duration Multiple Choice Questions Technical Subjects English 120 Questions 120 Marks 2 hours Previous year question papers for PGCET entrance exam for EEE: Q1. If A = - 0 1 2 1 0 3 2 2 is a singular matrix, then l is (A) 0 (B) -2 (C) 2 (D) -1 Q2. Let f x ex ( ) = in [0, 1]. Then, the value of c of the mean-value theorem is (A) 0.5 (B) ( ) e -1 (C) log ( ) e -1 (D) None Q3. If D u u u = + + xy yz zx x y z , then the value of A S × òò d is, where S is the surface of the cube defined by 0 1 £ £ x , 0 1 £ £ y , 0 1 £ £z (A) 0.5 (B) 3 (C) 0 (D) 1.5 Q4. The gradient of field f y x xyz = + 2 is (A) y y z x y z xy x y z ( ) ( ) + + + + u u u 2 (B) y x z x x z xy x y z ( ) ( )2 + + + + u u u (C) y yx xy x y z 2u u u + + 2 (D) y y z x y z xy x y z ( ) ( )2 2 + + + + u u u Q5. In the circuit of fig. Q5 the value of R1 will be (A) 25 W (B) 50 W (C) 100 W (D) 2000 W 1 Paper-1 Questions Q1. to Q20. carry one mark each. 100 V R1 – + 20 V – + 70 V R2 60 W Fig Q5 Q6. The voltage v o in fig. Q6 is always equal to (A) 1 V (B) 5 V (C) 9 V (D) None of the above Q7. Epitaxial growth is used in integrated circuit (A) because it produces low parasitic capacitance (B) because it yields back-to-back isolating junctions (C) to grow single crystal n -doped silicon on a single-crystal p -type substrate (D) to grow selectively single-crystal p -doped silicon of one resistivity on p -type substrate of a different resistivity. Q8. The chemical reaction involved in epitaxial growth in IC chips takes place at a temperature of about (A) 500° C (B) 800° C (C) 1200° C (D) 2000° C Q9. In the circuit of fig. Q9 the output voltage v o is (A) 2.67 V (B) -2.67 V (C) -6.67 V (D) 6.67 V Q10. Assertion (A) In the self bias CE transistor amplifier a single battery is used. Reason (R) The collector base junction is forward biased by VCC . Chose the correct option: (A) Both A and R individually true and R is the correct explanation of A. (B) Both A and R individually true and but R is not the correct explanation of A. (C) A is true but R is false (D) A is false 2 Paper-1 20 kW 20 kW 40 kW 60 kW -1 V +0.5 V +2 V vo Fig Q9 – + vo 5 V 1 A 4 W Q11. The address bus width of a memory of size 1024 ´ 8 bits is (A) 10 bits (B) 13 bits (C) 8 bits (D) 18 bits Q12. Consider the TTL circuit in fig Q12. The value ofVH andVL are respectively (A) 5 V, 0 V (B) 4.8 V, 0 V (C) 4.8 V, 0.2 V (D) 5 V, 0.2 V Q13. Consider a discrete-time system S whose response to a complex exponential input ej np 2 is specified as S e e j n j n : p p 2 3 2 Þ .The system is (A) definitely LTI (B) definitely not LTI (C) may be LTI (D) information is not sufficient. Q14. The DTFT of signal 2 4 2 d[ ] - n is (A) 22e- W j (B) 22ej W (C) 1 (D) None of the above Q15. Consider the List I and List II List I List II P. Derivative control 1. Improved overshoot response Q. Integral control 2. Less steady state errors R. Rate feed back control 3. Less stable S. Proportional control 4. More damping The correct match is P Q R S (A) 1 2 3 4 (B) 4 3 1 2 (C) 2 3 1 4 (D) 1 2 4 3 3 Paper-1 +5 V Vi Vo 4 kW 2 kW Q16. The pole–zero plot given in fig.Q16 is that of a (A) PID controller (B) PD controller (C) Integrator (D) Lag–lead compensating network Q17. In TDM non essential frequency components of the modulating signal are removed by (A) sampler (B) attenuator (C) pre-alias filter (C) modulator Q18. Coherent demodulation of FSK signal can be affected using (A) correlation receiver (B) bandpass filter and envelope detectors (C) discriminator detection (C) above all Q19. Two dissimilar antennas having their maximum directivities equal, (A) must have their beamwidths also equal. (B) can not have their beamwidths equal because they are dissimilar antenna. (C) may not necessarily have their maximum power gain equal. (D) must have their effective aperture areas ( capture areas) also equal. Q20. The dominant mode in a rectangular waveguide is TE10 because this mode has (A) no attenuation (B) no cut-off (C) no magnetic field component (D) the highest cut-off wavelength |
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